Answer: \((x, y) = (6, 1)\)
Let \(2x - 3y = 9\) ... (I) and \(2x + y = 13\) ... (II).
Multiply (II) by 3: \(6x + 3y = 39\)
Add the equations to eliminate \(y\):\[8x = 48\]\[x = 6\]
Substitute \(x = 6\) in (I): \(-3y = 9 - 12 = -3\), so \(y = 1\).
Check in (II): \(2(6) + 1(1) = 13\), which is true.