(I) \(x + y = 3\): \(x\): 3, \(\square\), \(\square\); \(y\): \(\square\), 5, 3; \((x, y)\): (3, 0), \(\square\), (0, 3)
(II) \(x - y = 4\): \(x\): \(\square\), −1, 0; \(y\): 0, \(\square\), −4; \((x, y)\): \(\square\), \(\square\), (0, −4)
Answer: x + y = 3 gives (3, 0), (−2, 5), (0, 3); x − y = 4 gives (4, 0), (−1, −5), (0, −4).
(I) \(x + y = 3\), so \(y = 3 - x\).
\(x = 3\): \(y = 0\). \(y = 5\): \(x = 3 - 5 = -2\). \(y = 3\): \(x = 0\).
| \(x\) | \(3\) | \(-2\) | \(0\) |
| \(y\) | \(0\) | \(5\) | \(3\) |
| \((x, y)\) | \((3, 0)\) | \((-2, 5)\) | \((0, 3)\) |
(II) \(x - y = 4\), so \(x = y + 4\).
\(y = 0\): \(x = 4\). \(x = -1\): \(-1 - y = 4\), so \(y = -5\). \(x = 0\): \(y = -4\).
| \(x\) | \(4\) | \(-1\) | \(0\) |
| \(y\) | \(0\) | \(-5\) | \(-4\) |
| \((x, y)\) | \((4, 0)\) | \((-1, -5)\) | \((0, -4)\) |
Plot these points and join each set to draw the two lines.
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