Answer: \((x, y) = (1, \frac{5}{2})\)
Ordered pairs for \(3x - 4y = -7\):
| \(x\) | \(-1\) | \(3\) | \(1\) |
| \(y\) | \(1\) | \(4\) | \(\frac{5}{2}\) |
| \((x, y)\) | \((-1, 1)\) | \((3, 4)\) | \((1, \frac{5}{2})\) |
Ordered pairs for \(5x - 2y = 0\):
| \(x\) | \(0\) | \(2\) | \(1\) |
| \(y\) | \(0\) | \(5\) | \(\frac{5}{2}\) |
| \((x, y)\) | \((0, 0)\) | \((2, 5)\) | \((1, \frac{5}{2})\) |
Plot both sets of points on the same graph paper (scale: 1 cm = 1 unit on both axes) and join each set to get two straight lines. The lines intersect at \((1, \frac{5}{2})\).
Check: \(3(1) + (-4)(\frac{5}{2}) = -7\) and \(5(1) + (-2)(\frac{5}{2}) = 0\) – both true.