Answer: \((x, y) = (2, 6)\)
In the form \(a_1x + b_1y = c_1\), \(a_2x + b_2y = c_2\):\[6x - 4y = -12\]\[8x - 3y = -2\]
\(D = \begin{vmatrix} 6 & -4 \\ 8 & -3 \end{vmatrix}\)\[D = 6\times (-3) - (-4)\times 8 = 14\]
\(D_x = \begin{vmatrix} -12 & -4 \\ -2 & -3 \end{vmatrix}\)\[D_x = (-12)\times (-3) - (-4)\times (-2) = 28\]
\(D_y = \begin{vmatrix} 6 & -12 \\ 8 & -2 \end{vmatrix}\)\[D_y = 6\times (-2) - (-12)\times 8 = 84\]
By Cramer's rule:\[x = \frac{D_x}{D} = \frac{28}{14} = 2\]\[y = \frac{D_y}{D} = \frac{84}{14} = 6\]