Answer: Father's age = 40 years, son's age = 15 years
Let the father's present age be \(x\) years and the son's be \(y\) years.
\(x + 2y = 70\) ... (I) and \(2x + y = 95\) ... (II)
Multiply (II) by 2: \(4x + 2y = 190\)
Subtract the equations to eliminate \(y\):\[-3x = -120\]\[x = 40\]
Substitute \(x = 40\) in (I): \(2y = 70 - 40 = 30\), so \(y = 15\).
Check in (II): \(2(40) + 1(15) = 95\), which is true.