Answer: \((x, y) = (3, 2)\)
Ordered pairs for \(2x + 3y = 12\):
| \(x\) | \(0\) | \(6\) | \(3\) |
| \(y\) | \(4\) | \(0\) | \(2\) |
| \((x, y)\) | \((0, 4)\) | \((6, 0)\) | \((3, 2)\) |
Ordered pairs for \(x - y = 1\):
| \(x\) | \(1\) | \(0\) | \(3\) |
| \(y\) | \(0\) | \(-1\) | \(2\) |
| \((x, y)\) | \((1, 0)\) | \((0, -1)\) | \((3, 2)\) |
Plot both sets of points on the same graph paper (scale: 1 cm = 1 unit on both axes) and join each set to get two straight lines. The lines intersect at \((3, 2)\).
Check: \(2(3) + 3(2) = 12\) and \(1(3) + (-1)(2) = 1\) – both true.