Answer: \((x, y) = (-2, -1)\)
Write \(3x - 2y + 4 = 0\) as \(3x - 2y = -4\).
Ordered pairs for \(x - 3y = 1\):
| \(x\) | \(1\) | \(4\) | \(-2\) |
| \(y\) | \(0\) | \(1\) | \(-1\) |
| \((x, y)\) | \((1, 0)\) | \((4, 1)\) | \((-2, -1)\) |
Ordered pairs for \(3x - 2y = -4\):
| \(x\) | \(0\) | \(2\) | \(-2\) |
| \(y\) | \(2\) | \(5\) | \(-1\) |
| \((x, y)\) | \((0, 2)\) | \((2, 5)\) | \((-2, -1)\) |
Plot both sets of points on the same graph paper (scale: 1 cm = 1 unit on both axes) and join each set to get two straight lines. The lines intersect at \((-2, -1)\).
Check: \(1(-2) + (-3)(-1) = 1\) and \(3(-2) + (-2)(-1) = -4\) – both true.