Answer: \((x, y) = (3, 1)\)
Ordered pairs for \(3x + y = 10\):
| \(x\) | \(0\) | \(2\) | \(3\) |
| \(y\) | \(10\) | \(4\) | \(1\) |
| \((x, y)\) | \((0, 10)\) | \((2, 4)\) | \((3, 1)\) |
Ordered pairs for \(x - y = 2\):
| \(x\) | \(0\) | \(2\) | \(3\) |
| \(y\) | \(-2\) | \(0\) | \(1\) |
| \((x, y)\) | \((0, -2)\) | \((2, 0)\) | \((3, 1)\) |
Plot both sets of points on the same graph paper (scale: 1 cm = 1 unit on both axes) and join each set to get two straight lines. The lines intersect at \((3, 1)\).
Check: \(3(3) + 1(1) = 10\) and \(1(3) + (-1)(1) = 2\) – both true.