Answer: S = {23, 25, 32, 35, 52, 53}, n(S) = 6
The tens digit can be any of 2, 3, 5 (3 ways); the units digit is one of the remaining two (2 ways). So \(3 \times 2 = 6\) numbers are possible: 23, 25, 32, 35, 52, 53.
Answer: S = {23, 25, 32, 35, 52, 53}, n(S) = 6
The tens digit can be any of 2, 3, 5 (3 ways); the units digit is one of the remaining two (2 ways). So \(3 \times 2 = 6\) numbers are possible: 23, 25, 32, 35, 52, 53.
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