There are 15 tickets in a box, each bearing one of the numbers from 1 to 15. One ticket is drawn at random from the box. Find the probability of event that the ticket drawn - (1) shows an even number. (2) shows a number which is a multiple of 5.

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: (1) 7/15 (2) 1/5

n(S) = 15

(1) A = {2, 4, 6, 8, 10, 12, 14}, n(A) = 7, \( P(A) = \frac{7}{15} \).

(2) B = {5, 10, 15}, n(B) = 3, \( P(B) = \frac{3}{15} = \frac{1}{5} \).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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