A box contains 30 tickets, bearing only one number from 1 to 30 on each. If one ticket is drawn at random, find the probability of an event that the ticket drawn bears (1) an odd number (2) a complete square number.

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: (1) 1/2 (2) 1/6

n(S) = 30

(1) Odd numbers 1, 3, ..., 29: 15 numbers. \( P = \frac{15}{30} = \frac{1}{2} \).

(2) Perfect squares: 1, 4, 9, 16, 25 (5 numbers). \( P = \frac{5}{30} = \frac{1}{6} \).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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