Answer: Central angles – Short of haemoglobin: 100°, Cataract: 20°, Respiratory disorders: 50°, Healthy: 190°
| Component | Value | Measure of central angle |
|---|---|---|
| Short of haemoglobin | 50 | \(\frac{50}{180} \times 360^\circ = 100^\circ\) |
| Cataract | 10 | \(\frac{10}{180} \times 360^\circ = 20^\circ\) |
| Respiratory disorders | 25 | \(\frac{25}{180} \times 360^\circ = 50^\circ\) |
| Healthy | 95 | \(\frac{95}{180} \times 360^\circ = 190^\circ\) |
| Total | 180 | \(360^\circ\) |
Draw a circle of any convenient radius and one radius in it. Using a protractor, draw sectors with the above central angles one after the other, and write the name of each component in its sector.
Healthy women \( = 180 - (50 + 10 + 25) = 95 \).