Answer: P, Q, R are collinear.
Three points are collinear if the sum of two of the distances equals the third.
\[PQ=\sqrt{3^2+(-1)^2}=\sqrt{10}\]
\[QR=\sqrt{3^2+(-1)^2}=\sqrt{10}\]
\[PR=\sqrt{6^2+(-2)^2}=\sqrt{40}=2\sqrt{10}\]
\(PQ+QR=2\sqrt{10}=PR\), so the points are collinear (Q is the midpoint of PR).