Answer: (-1, 0)
A point on the X-axis is P(x, 0). PA = PB, so \(PA^2=PB^2\):
\[(x+3)^2+(0-4)^2=(x-1)^2+(0+4)^2\]
\[x^2+6x+9+16=x^2-2x+1+16\]
\[8x=-8\ \Rightarrow\ x=-1\]
The required point is (-1, 0).
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Doubtly AI
· 24 Oct 2026
AI-verified · Oct 2026
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