Answer: x = 7 or x = -5
\[LM^2=(1-x)^2+(15-7)^2=100\]
\[(1-x)^2+64=100\]
\[(1-x)^2=36\ \Rightarrow\ 1-x=\pm6\]
So \(x=1-6=-5\) or \(x=1+6=7\).
Answer: x = 7 or x = -5
\[LM^2=(1-x)^2+(15-7)^2=100\]
\[(1-x)^2+64=100\]
\[(1-x)^2=36\ \Rightarrow\ 1-x=\pm6\]
So \(x=1-6=-5\) or \(x=1+6=7\).
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