Answer: AB = BC = AC = 4, so ΔABC is equilateral.
\[AB=\sqrt{0^2+4^2}=4\]
\[BC=\sqrt{(2\sqrt3)^2+(4-6)^2}=\sqrt{12+4}=4\]
\[AC=\sqrt{(2\sqrt3)^2+(4-2)^2}=\sqrt{12+4}=4\]
All three sides are equal, so A, B, C are vertices of an equilateral triangle.
Answer: AB = BC = AC = 4, so ΔABC is equilateral.
\[AB=\sqrt{0^2+4^2}=4\]
\[BC=\sqrt{(2\sqrt3)^2+(4-6)^2}=\sqrt{12+4}=4\]
\[AC=\sqrt{(2\sqrt3)^2+(4-2)^2}=\sqrt{12+4}=4\]
All three sides are equal, so A, B, C are vertices of an equilateral triangle.
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