Answer: P(1, 3)
Section formula: if P divides AB in the ratio \(m:n\), then \(P=\left(\dfrac{mx_2+nx_1}{m+n},\ \dfrac{my_2+ny_1}{m+n}\right)\).
Here \(m=2,\ n=3\), A(-1, 7), B(4, -3).
\[x=\frac{2(4)+3(-1)}{5}=\frac{5}{5}=1\]
\[y=\frac{2(-3)+3(7)}{5}=\frac{15}{5}=3\]