Answer: B(-6, 3)
The centre is the midpoint of a diameter. Let B = (x, y).
\[\frac{2+x}{2}=-2\ \Rightarrow\ x=-6\]
\[\frac{-3+y}{2}=0\ \Rightarrow\ y=3\]
Answer: B(-6, 3)
The centre is the midpoint of a diameter. Let B = (x, y).
\[\frac{2+x}{2}=-2\ \Rightarrow\ x=-6\]
\[\frac{-3+y}{2}=0\ \Rightarrow\ y=3\]
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