Answer: h = 7, k = 18
Centroid \(G=\left(\dfrac{x_1+x_2+x_3}{3},\ \dfrac{y_1+y_2+y_3}{3}\right)\).
\[\frac{h+2-6}{3}=1\ \Rightarrow\ h-4=3\ \Rightarrow\ h=7\]
\[\frac{-6+3+k}{3}=5\ \Rightarrow\ k-3=15\ \Rightarrow\ k=18\]
Answer: h = 7, k = 18
Centroid \(G=\left(\dfrac{x_1+x_2+x_3}{3},\ \dfrac{y_1+y_2+y_3}{3}\right)\).
\[\frac{h+2-6}{3}=1\ \Rightarrow\ h-4=3\ \Rightarrow\ h=7\]
\[\frac{-6+3+k}{3}=5\ \Rightarrow\ k-3=15\ \Rightarrow\ k=18\]
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