Answer: (0, 2) and (-2, -3)
The points of trisection P and Q divide AB in the ratios 1 : 2 and 2 : 1.
P (1 : 2): \(x=\dfrac{1(-4)+2(2)}{3}=0\), \(y=\dfrac{1(-8)+2(7)}{3}=2\). So P(0, 2).
Q (2 : 1): \(x=\dfrac{2(-4)+1(2)}{3}=-2\), \(y=\dfrac{2(-8)+1(7)}{3}=-3\). So Q(-2, -3).