Answer: The points are collinear.
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
Slope of AB = \(\dfrac{1+1}{0+1}=2\)
Slope of BC = \(\dfrac{3-1}{1-0}=2\)
The slopes are equal and the two segments share a point, so the points lie on one line.
Answer: The points are collinear.
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
Slope of AB = \(\dfrac{1+1}{0+1}=2\)
Slope of BC = \(\dfrac{3-1}{1-0}=2\)
The slopes are equal and the two segments share a point, so the points lie on one line.
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