Answer: The points are collinear.
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
Slope of DE = \(\dfrac{0+3}{1+2}=1\)
Slope of EF = \(\dfrac{1-0}{2-1}=1\)
The slopes are equal and the two segments share a point, so the points lie on one line.
Answer: The points are collinear.
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
Slope of DE = \(\dfrac{0+3}{1+2}=1\)
Slope of EF = \(\dfrac{1-0}{2-1}=1\)
The slopes are equal and the two segments share a point, so the points lie on one line.
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