Answer: The points are collinear.
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
Slope of AK = \(\dfrac{\frac52-4}{-2+4}=\dfrac{-\frac32}{2}=-\dfrac34\)
Slope of KN = \(\dfrac{-2-\frac52}{4+2}=\dfrac{-\frac92}{6}=-\dfrac34\)
The slopes are equal and the two segments share a point, so the points lie on one line.