Answer: Slope of AB = -5, slope of BC = 1/5, slope of AC = -2/3
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
AB: \(\dfrac{4-(-1)}{0-1}=\dfrac{5}{-1}=-5\)
BC: \(\dfrac{3-4}{-5-0}=\dfrac{-1}{-5}=\dfrac15\)
AC: \(\dfrac{3-(-1)}{-5-1}=\dfrac{4}{-6}=-\dfrac23\)
Answer: Slope of AB = -5, slope of BC = 1/5, slope of AC = -2/3
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
AB: \(\dfrac{4-(-1)}{0-1}=\dfrac{5}{-1}=-5\)
BC: \(\dfrac{3-4}{-5-0}=\dfrac{-1}{-5}=\dfrac15\)
AC: \(\dfrac{3-(-1)}{-5-1}=\dfrac{4}{-6}=-\dfrac23\)
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