Answer: The points are collinear.
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
Slope of AB \(=\dfrac{-0.5-2}{1-0}=-2.5\); slope of BC \(=\dfrac{-3+0.5}{2-1}=-2.5\).
The slopes are equal and B is common, so A, B, C are collinear.
Answer: The points are collinear.
Slope \(=\dfrac{y_2-y_1}{x_2-x_1}\).
Slope of AB \(=\dfrac{-0.5-2}{1-0}=-2.5\); slope of BC \(=\dfrac{-3+0.5}{2-1}=-2.5\).
The slopes are equal and B is common, so A, B, C are collinear.
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