Answer: No, the points are collinear, so no triangle is formed.
Distance formula: \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\).
\[PQ=\sqrt{(-2)^2+4^2}=\sqrt{20}=2\sqrt5\]
\[QR=\sqrt{(-1)^2+2^2}=\sqrt5\]
\[PR=\sqrt{(-3)^2+6^2}=\sqrt{45}=3\sqrt5\]
\(PQ+QR=2\sqrt5+\sqrt5=3\sqrt5=PR\), so P, Q, R lie on one line.