Answer: k = 5
\[\frac{k-(-3)}{4-(-12)}=\frac12\ \Rightarrow\ \frac{k+3}{16}=\frac12\]
\[k+3=8\ \Rightarrow\ k=5\]
Answer: k = 5
\[\frac{k-(-3)}{4-(-12)}=\frac12\ \Rightarrow\ \frac{k+3}{16}=\frac12\]
\[k+3=8\ \Rightarrow\ k=5\]
Log in or create a free account to answer this question.