Find the lengths of the medians of a triangle whose vertices are A(-1, 1), B(5, -3) and C(3, 5).

Doubtly Asked 24 Oct 2026 Save WhatsApp Report

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Answer: AD = 5, BE = 2√13, CF = √37

Midpoints: D of BC \(=(4,1)\), E of CA \(=(1,3)\), F of AB \(=(2,-1)\).

\[AD=\sqrt{(4+1)^2+(1-1)^2}=5\]

\[BE=\sqrt{(1-5)^2+(3+3)^2}=\sqrt{52}=2\sqrt{13}\]

\[CF=\sqrt{(2-3)^2+(-1-5)^2}=\sqrt{37}\]

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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