If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls, is

\(A) {{55\over3}({2\over3})^{11}} \)

\(B) {{55}({2\over3})^{10}} \)

\(C){{220}({1\over3})^{12}} \)

\(D){{22}({1\over3})^{11}} \)