Q.2 (A)(i) Complete the following table for drawing the graph of the equation : \(x + 2y = 4\)
| \(x\) | –2 | 0 | ____ |
| \(y\) | ____ | 2 | 1 |
| \((x, y)\) | ____ | (0, 2) | ____ |
Best answer
Answer: \(y = 3\) when \(x = -2\); \(x = 2\) when \(y = 1\); points (–2, 3) and (2, 1).
Substitute in \(x + 2y = 4\) :
When \(x = -2\) : \(-2 + 2y = 4\), so \(2y = 6\), \(y = 3\) → (–2, 3).
When \(y = 1\) : \(x + 2 = 4\), so \(x = 2\) → (2, 1).
The completed table is \(x\) : –2, 0, 2; \(y\) : 3, 2, 1; \((x, y)\) : (–2, 3), (0, 2), (2, 1). Plotting these three points and joining them gives the line \(x + 2y = 4\).
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