Answer: \(m = 1\), \(n = 4\)
\(D = \begin{vmatrix} 4 & -2 \\ 4 & 3 \end{vmatrix} = 12 - (-8) = 20\)
\(D_m = \begin{vmatrix} -4 & -2 \\ 16 & 3 \end{vmatrix} = -12 - (-32) = 20\)
\(D_n = \begin{vmatrix} 4 & -4 \\ 4 & 16 \end{vmatrix} = 64 - (-16) = 80\)
\(m = \dfrac{D_m}{D} = \dfrac{20}{20} = 1\), \(n = \dfrac{D_n}{D} = \dfrac{80}{20} = 4\).
Check : \(4(1) - 2(4) = -4\) ✓, \(4(1) + 3(4) = 16\) ✓