Answer: the 63rd term
\(a = 2\), \(d = 11 - 2 = 9\).
\(t_n = a + (n - 1)d = 560\)
\(2 + (n - 1)9 = 560 \Rightarrow (n - 1)9 = 558 \Rightarrow n - 1 = 62 \Rightarrow n = 63\).
Best answer
Answer: the 63rd term
\(a = 2\), \(d = 11 - 2 = 9\).
\(t_n = a + (n - 1)d = 560\)
\(2 + (n - 1)9 = 560 \Rightarrow (n - 1)9 = 558 \Rightarrow n - 1 = 62 \Rightarrow n = 63\).
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