Answer: \(t_{24} = 104\)
Here \(a = 12\), \(d = 16 - 12 = 4\), \(n = 24\).
\(t_n = a + (n - 1)d\)
\(t_{24} = 12 + (24 - 1) \times 4 = 12 + 92 = 104\).
Best answer
Answer: \(t_{24} = 104\)
Here \(a = 12\), \(d = 16 - 12 = 4\), \(n = 24\).
\(t_n = a + (n - 1)d\)
\(t_{24} = 12 + (24 - 1) \times 4 = 12 + 92 = 104\).
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