Answer: \(\bar{x} = 2100\)
\(\bar{x} = A + \dfrac{\sum f_i d_i}{\sum f_i}\)
\(\bar{x} = 2000 + \dfrac{10000}{100} = 2000 + 100 = 2100\).
Best answer
Answer: \(\bar{x} = 2100\)
\(\bar{x} = A + \dfrac{\sum f_i d_i}{\sum f_i}\)
\(\bar{x} = 2000 + \dfrac{10000}{100} = 2000 + 100 = 2100\).
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