The following table shows the funds collected by 105 students for flood affected people. Find the median of the data.Fund (Rupees)No. of Students10—201020—303730—401540—502050—60760—70870—808

Answer: Median \(= 33.67\) (approximately ₹ 33.67)

\(N = 105\), so \(\dfrac{N}{2} = 52.5\). Cumulative frequencies: 10, 47, 62, 82, 89, 97, 105.

The cumulative frequency first exceeds 52.5 in the class 30—40, so 30—40 is the median class:
\(L = 30\), \(cf = 47\), \(f = 15\), \(h = 10\).

Median \(= L + \left(\dfrac{\frac{N}{2} - cf}{f}\right) \times h = 30 + \left(\dfrac{52.5 - 47}{15}\right) \times 10\)

\(= 30 + \dfrac{5.5}{15} \times 10 = 30 + 3.67 = 33.67\).

So the median fund is about ₹ 33.67.