Answer: \(x = 3\), \(y = -2\)
\(D = \begin{vmatrix} 1 & 2 \\ 2 & -3 \end{vmatrix} = -3 - 4 = -7\)
\(D_x = \begin{vmatrix} -1 & 2 \\ 12 & -3 \end{vmatrix} = 3 - 24 = -21\)
\(D_y = \begin{vmatrix} 1 & -1 \\ 2 & 12 \end{vmatrix} = 12 + 2 = 14\)
\(x = \dfrac{D_x}{D} = \dfrac{-21}{-7} = 3\), \(y = \dfrac{D_y}{D} = \dfrac{14}{-7} = -2\).