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Maharashtra SSC Algebra (Mathematics Part I) Board Paper June 2026

Written board papers, 40 marks and 2 hours each: Science & Technology Part 1 and 2, Algebra, Geometry and more.

2026, June 120 minutes 40 marks Save WhatsApp

Sections

Q.1 (A) Choose the correct alternative (4 marks) 4 questions
Q.1 (B) Solve the following subquestions (4 marks) 4 questions
Q.2 (A) Complete and rewrite any two activities (4 marks) 3 questions
Q.2 (B) Solve any four subquestions (8 marks) 5 questions
Q.3 (A) Complete and rewrite any one activity (3 marks) 2 questions
Q.3 (B) Solve any two subquestions (6 marks) 4 questions
Q.4 Solve any two subquestions (8 marks) 2 questions
Q.5 Solve any one subquestion (3 marks) 2 questions

About the June 2026 SSC Algebra board paper

This is the Mathematics Part I (Algebra) paper set by the Maharashtra State Board for the Class 10 examination of June 2026, held on 22 June 2026 (English medium, Revised Course, paper code N 384). It is a 2-hour paper for 40 marks and calculators are not allowed. The pattern is: four MCQs and four one-mark questions in Q.1, activities and short sums in Q.2 and Q.3 (with internal choice), two 4-mark sums of Q.4, and a 3-mark application question in Q.5.

All six Algebra chapters appear. The paper tests determinants and Cramer's rule for simultaneous equations, forming and solving quadratic equations (factorisation and formula), an A.P. with a decreasing monthly repayment, GST and CGST/SGST with input tax credit, shares at par, premium and discount, probability with coins, a die and two-digit numbers, and statistics through the mean, the mode and the angles of a pie diagram.

Chapters covered

Instructions

Solve on paper with a timer, then check against the solutions.

Q.1 (A) Choose the correct alternative (4 marks)

  1. Q.1 (A)(i) For solving the simultaneous equations \(x + y = 3\), \(3x - 2y = 4\). Find the value of determinant D.

    1. (A) 5
    2. (B) 1
    3. (C) –5
    4. (D) –1
    1 mark See answer →

  2. Q.1 (A)(ii) One of the roots of equation \(x^2 + mx - 5 = 0\) is 2, find the value of \(m\).

    1. (A) –2
    2. (B) \(-\dfrac{1}{2}\)
    3. (C) \(\dfrac{1}{2}\)
    4. (D) 2
    1 mark See answer →

  3. Q.1 (A)(iii) Rate of GST on brokerage is …………… .

    1. (A) 5%
    2. (B) 18%
    3. (C) 12%
    4. (D) 28%
    1 mark See answer →

  4. Q.1 (A)(iv) The classification of persons based on blood groups is to be shown by a pie diagram. The persons having blood group O are 40%. What should be the measure of angle for the persons having O blood group ?

    1. (A) 114º
    2. (B) 140º
    3. (C) 104º
    4. (D) 144º
    1 mark See answer →

Q.1 (B) Solve the following subquestions (4 marks)

  1. Q.1 (B)(i) If \(15x + 17y = 21\) and \(17x + 15y = 11\), then find the value of \(x + y\).

    1 mark See answer →

  2. Q.1 (B)(ii) Find the first term and common difference of the given A.P. 5, 1, –3, –7, ……

    1 mark See answer →

  3. Q.1 (B)(iii) Two coins are tossed simultaneously. Write the sample space (S) and the number of sample points \(n(S)\).

    1 mark See answer →

  4. Q.1 (B)(iv) Find Mean \((\bar{X})\) if \(\sum x_i f_i = 1265\) and \(\sum f_i = 50\).

    1 mark See answer →

Q.2 (A) Complete and rewrite any two activities (4 marks)

  1. Q.2 (A)(i) Complete the following table to draw the graph of equation \(x - y = 1\).

    Activity :

    \(x\)0________
    \(y\)____0–3
    \((x, y)\)(0, –1)____(–2, –3)
    2 marks See answer →

  2. Q.2 (A)(ii) Complete the following table by writing suitable numbers and words.

    Activity :

    Sr. No.FVShare is atMV
    (1)₹ 100Par₹ ____
    (2)₹ ____Premium ₹ 500₹ 575
    (3)₹ 10____₹ 5
    (4)₹ 300____₹ 310
    2 marks See answer →

  3. Q.2 (A)(iii) Complete the following activity to find the probability of getting tail when one coin is tossed.

    Activity :

    Let ‘S’ be the sample space.
    \(S = \{H, T\}\)
    \(n(S) = \) ____
    Let A be the event of getting tail.
    \(A = \{\) ____ \(\}\)
    \(\therefore n(A) = \) ____
    \(P(A) = \dfrac{n(A)}{n(S)}\)
    \(P(A) = \) ____

    2 marks See answer →

Q.2 (B) Solve any four subquestions (8 marks)

  1. Q.2 (B)(i) Solve the following simultaneous equations : \(5x + 3y = 9\); \(2x - 3y = 12\)

    2 marks See answer →

  2. Q.2 (B)(ii) Form the quadratic equation whose roots are 3 and –10.

    2 marks See answer →

  3. Q.2 (B)(iii) ‘Pawan Medical’ supplies medicines. On some medicines the rate of GST is 12%, then what is the rate of CGST and SGST ?

    2 marks See answer →

  4. Q.2 (B)(iv) Solve the following quadratic equation by factorisation method : \(25m^2 = 9\)

    2 marks See answer →

  5. Q.2 (B)(v) If one die is rolled, then write the sample space (S), \(n(S)\), event A in the set form and \(n(A)\).
    Event A : getting odd number on the upper face.

    2 marks See answer →

Q.3 (A) Complete and rewrite any one activity (3 marks)

  1. Q.3 (A)(i) M/s. Jay Chemicals purchased a liquid soap having taxable value ₹ 8,000 and sold it to the consumers for the taxable value ₹ 10,000. Rate of GST is 18%. Find the CGST and SGST payable by M/s. Jay Chemicals.

    Activity :

    Input Tax \(= 18\%\) of 8000 \(= \dfrac{\text{____}}{100} \times 8000 = \) ₹ ____

    \(\therefore\) ITC \(= \) ₹ 1440

    Output Tax \(= 18\%\) of 10,000 \(= \dfrac{18}{100} \times \) ____ \(= \) ₹ ____

    \(\therefore\) GST payable = Output tax – ____ \(= \) ____ \(- 1440 = \) ₹ 360

    \(\therefore\) Payable CGST = ₹ 180 and Payable SGST = ₹ 180 by M/s. Jay Chemicals.

    3 marks See answer →

  2. Q.3 (A)(ii) Complete the following activity to find, ‘how many three digit natural numbers which are divisible by 5’.

    Activity :

    Three digit natural numbers divisible by 5 are as follows :
    100, 105, 110, ……………, 995.

    \(t_n = \) ____, \(a = \) ____, \(d = 5\), \(n = ?\)

    \(t_n = a + (n - 1)d\) …………… formula

    \(995 = \) ____ \(+ (n - 1) \times \) ____

    \(895 = (n - 1) \times 5\)

    \(\dfrac{895}{5} = n - 1\)

    ____ \(+ 1 = n\)

    ____ \(= n\)

    \(\therefore\) There are 180 three digit natural numbers, divisible by 5.

    3 marks See answer →

Q.3 (B) Solve any two subquestions (6 marks)

  1. Q.3 (B)(i) Solve the following simultaneous equations by Cramer’s rule : \(x + 2y = -1\); \(2x - 3y = 12\)

    3 marks See answer →

  2. Q.3 (B)(ii) Solve the following quadratic equation by formula method : \(x^2 - 3x - 2 = 0\)

    3 marks See answer →

  3. Q.3 (B)(iii) Electricity used by some families is shown in the following table. Find the mode of electricity used.

    Use of Electricity (Units)0—2020—4040—6060—8080—100100—120
    No. of Families1350701008017
    3 marks See answer →

  4. Q.3 (B)(iv) A two digit number is formed using digits 2, 3, 5, 7, 9 without repetition. What is the probability that the number formed is :
    (a) an odd number.
    (b) a multiple of 5.

    3 marks See answer →

Q.4 Solve any two subquestions (8 marks)

  1. Q.4 (ii) The sum of the squares of five consecutive natural numbers is 1455. Find the numbers.

    4 marks See answer →

  2. Q.4 (iii) Ajay Sharma repays the borrowed amount of ₹ 3,25,000 by paying ₹ 30,500 in the first month and then decreases the payment by ₹ 1,500 every month. How long will it take to clear his amount ?

    4 marks See answer →

Q.5 Solve any one subquestion (3 marks)

  1. Q.5 (i) If the point (2, 1) lies on the graph of the equation \(x + ay = 4\), then find the value of ‘a’ and draw the graph of the equation so obtained.

    3 marks See answer →

  2. Q.5 (ii) The following pie diagram represents the number of valid votes obtained by four students; who contested for school captain. The total of valid votes polled was 720.

    [Pie diagram: Ram 100°, Raj 80°, Shubha 120°, Radha 60°]

    Answer the following questions :
    (a) Who has won the election ?
    (b) What is the minimum number of votes ? Who got it ?
    (c) By how many votes did the winner defeat the nearest contestant ?

    3 marks See answer →