Q.1 (A)(iii) For an A.P., t₇ = 4 , d = -4 , then a = ......................... A. 6 B. 7 C. 20 D. 28

Answer: D. 28 Answer: (D) 28 t_n = a + (n-1)d , so t₇ = a + 6d . 4 = a + 6(-4) ⇒ 4 = a - 24 ⇒ a = 28 .

For an A.P., \(t_7 = 4\), \(d = -4\), then \(a\) = .........................

Q.1 (A)(iii) For an A.P., \(t_7 = 4\), \(d = -4\), then \(a\) = .........................

A. 6

B. 7

C. 20

D. 28

Doubtly Asked 25 Oct 2026 ssc 10th Save WhatsApp Report

Best answer

Answer: D. 28

Answer: (D) 28

\(t_n = a + (n-1)d\), so \(t_7 = a + 6d\).

\(4 = a + 6(-4) \Rightarrow 4 = a - 24 \Rightarrow a = 28\).

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report

Was this answer helpful?