Answer: \(P(A) = \dfrac{3}{4}\)
\(S = \{\text{HH, HT, TH, TT}\}\), so \(n(S) = 4\).
Event A : getting at least one head, \(A = \{\text{HH, HT, TH}\}\), so \(n(A) = 3\).
\(P(A) = \dfrac{n(A)}{n(S)} = \dfrac{3}{4}\).
Best answer
Answer: \(P(A) = \dfrac{3}{4}\)
\(S = \{\text{HH, HT, TH, TT}\}\), so \(n(S) = 4\).
Event A : getting at least one head, \(A = \{\text{HH, HT, TH}\}\), so \(n(A) = 3\).
\(P(A) = \dfrac{n(A)}{n(S)} = \dfrac{3}{4}\).
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