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One of the roots of the quadratic equation \(5m^2 + 2m + k = 0\) is \(\dfrac{-7}{5}\). Complete the following activity to find the value of ‘\(k\)’.Solution :\(\dfrac{-7}{5}\) is a root of quadratic equation \(5m^2 + 2m + k = 0\).\(\therefore\) put \…

Q.3 (A)(ii) One of the roots of the quadratic equation \(5m^2 + 2m + k = 0\) is \(\dfrac{-7}{5}\). Complete the following activity to find the value of ‘\(k\)’.

Solution :

\(\dfrac{-7}{5}\) is a root of quadratic equation \(5m^2 + 2m + k = 0\).
\(\therefore\) put \(m = \dfrac{-7}{5}\) in the equation.
\(\therefore 5 \times \left(\text{____}\right)^2 + 2 \times \left(\text{____}\right) + k = 0\)
____ \(+\) ____ \(+ k = 0\)
____ \(+ k = 0\)
\(\therefore k =\) ____

1 answer

Best answer

Answer: \(k = -7\)

Since \(\dfrac{-7}{5}\) is a root, put \(m = \dfrac{-7}{5}\) in \(5m^2 + 2m + k = 0\):

\(5 \times \left(\dfrac{-7}{5}\right)^2 + 2 \times \left(\dfrac{-7}{5}\right) + k = 0\)

\(5 \times \dfrac{49}{25} + \left(\dfrac{-14}{5}\right) + k = 0\)

\(\dfrac{49}{5} - \dfrac{14}{5} + k = 0\)

\(\dfrac{35}{5} + k = 0\), i.e. \(7 + k = 0\)

\(\therefore k = -7\).

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report
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