Answer: Slope of PQ = slope of QR = \(-\frac{1}{3}\), so P, Q, R are collinear.
Slope of PQ \(= \dfrac{2 - 3}{1 - (-2)} = \dfrac{-1}{3}\).
Slope of QR \(= \dfrac{1 - 2}{4 - 1} = \dfrac{-1}{3}\).
The two slopes are equal and Q is a common point, so the three points lie on one line. Hence P, Q, R are collinear.