If \(\Delta PQR \sim \Delta LMN\), \(9 \times A(\Delta PQR) = 16 \times A(\Delta LMN)\) and QR = 20, then find MN.
Q.3 (B)(4) If \(\Delta PQR \sim \Delta LMN\), \(9 \times A(\Delta PQR) = 16 \times A(\Delta LMN)\) and QR = 20, then find MN.
Q.3 (B)(4) If \(\Delta PQR \sim \Delta LMN\), \(9 \times A(\Delta PQR) = 16 \times A(\Delta LMN)\) and QR = 20, then find MN.
Best answer
Answer: MN = 15
\(9 \times A(\Delta PQR) = 16 \times A(\Delta LMN)\), so \(\dfrac{A(\Delta PQR)}{A(\Delta LMN)} = \dfrac{16}{9}\).
For similar triangles the ratio of areas equals the ratio of the squares of corresponding sides: \(\dfrac{QR^2}{MN^2} = \dfrac{16}{9}\), so \(\dfrac{QR}{MN} = \dfrac{4}{3}\).
\(\therefore MN = \dfrac{3}{4}\times 20 = 15\).
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