Answer: \(10\sqrt2\) cm (≈ 14.14 cm)
Each diagonal of a square of side \(a\) is \(a\sqrt2\): in right \(\Delta ABC\), \(AC^2 = AB^2 + BC^2 = 10^2 + 10^2 = 200\), so \(AC = \sqrt{200} = 10\sqrt2\) cm ≈ 14.14 cm.
Best answer
Answer: \(10\sqrt2\) cm (≈ 14.14 cm)
Each diagonal of a square of side \(a\) is \(a\sqrt2\): in right \(\Delta ABC\), \(AC^2 = AB^2 + BC^2 = 10^2 + 10^2 = 200\), so \(AC = \sqrt{200} = 10\sqrt2\) cm ≈ 14.14 cm.
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