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In the following figure, chord EN and chord FS intersect each other at point M in the exterior of the circle. If \(m(\text{arc } NS) = 125^\circ\), \(m(\text{arc } EF) = 37^\circ\), then complete the following activity to find \(\angle NMS\).[Figure:…

Q.2 (A)(i) In the following figure, chord EN and chord FS intersect each other at point M in the exterior of the circle. If \(m(\text{arc } NS) = 125^\circ\), \(m(\text{arc } EF) = 37^\circ\), then complete the following activity to find \(\angle NMS\).

[Figure: M is a point outside the circle; one secant from M cuts the circle at E and then N (M – E – N) and the other cuts it at F and then S (M – F – S); both secants are extended with arrows beyond N and S.]

Activity : Chord EN and chord FS intersect each other at point M in the exterior of the circle.

\(m\angle NMS = \dfrac{1}{2}\left[\text{____} - m(\text{arc } EF)\right]\)
= \(\dfrac{1}{2}\left[\text{____} - 37\right]\)
= \(\dfrac{1}{2} \times \text{____}\)
\(\therefore m\angle NMS = \text{____}\)

1 answer

Best answer

Answer: the blanks are \(m(\text{arc } NS) = 125\), 125, 88 and \(m\angle NMS = 44^\circ\).

Activity completed:

\(m\angle NMS = \dfrac{1}{2}\left[125 - m(\text{arc } EF)\right]\)
= \(\dfrac{1}{2}\left[125 - 37\right]\)
= \(\dfrac{1}{2} \times 88\)
\(\therefore m\angle NMS = 44^\circ\)

(Theorem of the angle formed by two secants meeting outside the circle: the angle is half the difference of the measures of the intercepted arcs.)

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report
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