Q.2 (B)(i) In the following figure, in Δ PQR , seg RS bisects ∠ R . If PR = 15, QR = 20, PS = 12, then find QS. [Figure: Δ PQR with P at the lower left, Q at the lower right and R at the top; S is on side PQ; seg RS is drawn and the two equal parts of ∠ PRQ are marked.]

Answer: QS = 16 In Δ PQR , ray RS bisects ∠ PRQ , so by the angle bisector theorem, PS/QS = PR/QR 12/QS = 15/20 = 3/4 , so QS = 12 × 4/3 = 16 .

In the following figure, in \(\Delta PQR\), seg RS bisects \(\angle R\). If PR = 15, QR = 20, PS = 12, then find QS.[Figure: \(\Delta PQR\) with P at the lower left, Q at the lower right and R at the top; S is on side PQ; seg RS is drawn and the two…

Q.2 (B)(i) In the following figure, in \(\Delta PQR\), seg RS bisects \(\angle R\). If PR = 15, QR = 20, PS = 12, then find QS.

[Figure: \(\Delta PQR\) with P at the lower left, Q at the lower right and R at the top; S is on side PQ; seg RS is drawn and the two equal parts of \(\angle PRQ\) are marked.]

Doubtly Asked 25 Oct 2026 ssc 10th Save WhatsApp Report

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Answer: QS = 16

In \(\Delta PQR\), ray RS bisects \(\angle PRQ\), so by the angle bisector theorem,

\(\dfrac{PS}{QS} = \dfrac{PR}{QR}\)

\(\dfrac{12}{QS} = \dfrac{15}{20} = \dfrac{3}{4}\), so \(QS = \dfrac{12 \times 4}{3} = 16\).

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report

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In the following figure, in \(\Delta PQR\), seg RS bisects \(\angle R\). If PR = 15, QR = 20, PS = 12, then find QS.[Figure: \(\Delta PQR\) with P at the lower left, Q at the lower right and R at the top; S is on side PQ; seg RS is drawn and the two…

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