6.02 × 1020 molecules of urea are present in 100 ml of its solution. Jee

6.02 × 10²⁰ molecules of urea are present in 100 ml of its solution. The concentration of urea solution is

A)0.02M

B) 0.01 M

C)0.001M

D)0.05 M

Asked 20 Jul 2021 Updated 23 Oct 2026 Student doubt Save WhatsApp Report

1 answer

Answer: B) 0.01 M

Moles of urea:

\[n = \frac{6.02\times10^{20}}{6.02\times10^{23}} = 1\times10^{-3}\ \text{mol}\]

Volume of solution \(= 100\ \text{mL} = 0.1\ \text{L}\).

\[\text{Molarity} = \frac{10^{-3}\ \text{mol}}{0.1\ \text{L}} = 0.01\ \text{M}\]

Doubtly AI · 23 Oct 2026 AI-verified · Oct 2026 Report

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