Q.2 (B)(iii) Complete the following reaction and give name of products :
\(\mathrm{CuSO_4(aq) + Fe(s) \rightarrow ......... + .........}\)
Best answer
Answer: \(\mathrm{CuSO_4 + Fe \rightarrow FeSO_4 + Cu}\); the products are iron(II) sulphate and copper.
Iron is more reactive than copper, so it displaces copper from copper sulphate solution. The blue colour of the solution slowly fades to pale green as iron sulphate is formed, and reddish-brown copper is deposited on the iron:
\[\mathrm{CuSO_4(aq) + Fe(s) \rightarrow FeSO_4(aq) + Cu(s)}\]
It is a displacement (redox) reaction.
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