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A block of mass m, lying on a smooth horizontal surface, is attached to a spring (of negligible mass) of spring constant k. The other end of the spring is fixed, as shown in the figure. The block is initally at rest in its equilibrium position. If now the block is pulled with a constant force F, the maximum speed of the block is : 

A)πFmk 

B)2Fmk 

C)Fmk 

D)Fπmk

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Best answer

the correct answer is option C) Fmk 

Detailed solution:: 

Maximum speed is at mean position (equilibrium). F = kx

x=Fk 

WF+Wsp=ΔKE 

F(x)12kx2=12mv20 

F(Fk)12k(Fk)2=12mv2 

vmax=Fmk 

 

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