Explain CE configuration of BJT with the input and output characteristics.
Q.4 (b) Explain CE configuration of BJT with the input and output characteristics.
Q.4 (b) Explain CE configuration of BJT with the input and output characteristics.
Best answer
Common-emitter (CE) configuration: emitter is common to input and output. Input is applied between base and emitter (VBE, IB); output is taken between collector and emitter (VCE, IC). For an NPN transistor, VBB forward biases the B-E junction and VCC reverse biases the C-B junction.
I_C -> Rc (mA)
+----------C
I_B | | NPN
V_BB +-RB---B ----| V_CC
| E
+----------+--------+
(common)
Input characteristics (IB vs VBE at constant VCE): similar to a forward-biased diode; IB is negligible until VBE ≈ 0.7 V (Si) cut-in, then rises rapidly. Increasing VCE shifts the curve slightly right (early effect / base-width modulation). Input resistance \( r_i = \Delta V_{BE}/\Delta I_B \) is about 1 kΩ (medium).
I_B(uA) VCE=1V VCE=10V | / / | / / | _/ _/ +----------0.7-------- V_BE (V)
Output characteristics (IC vs VCE for different IB):
I_C(mA) ______________ I_B = 60 uA | /______________________ I_B = 40 uA | /_______________________ I_B = 20 uA |/________________________ I_B = 0 (cut-off) +--------------------------- V_CE (V) saturation | active region
Output resistance \( r_o = \Delta V_{CE}/\Delta I_C \) is high (≈ 10 to 50 kΩ). Current gain \( \beta = \Delta I_C/\Delta I_B \) (50 to 300). CE gives high current, voltage and power gain with 180° phase shift; most widely used (amplifiers, switches).
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