Q.1 (x) In series LCR circuit for X_L > X_C , tanφ will be _____. A. negative B. zero C. positive D. infinity

Answer: C. positive Answer: (c) positive For a series LCR circuit tanφ = X_L - X_C/R . When X_L > X_C the numerator is positive, so tanφ is positive: the voltage leads the current and the circuit is inductive.

In series LCR circuit for \(X_L > X_C\), \(\tan\phi\) will be _____.

Q.1 (x) In series LCR circuit for \(X_L > X_C\), \(\tan\phi\) will be _____.

A. negative

B. zero

C. positive

D. infinity

Doubtly Asked 27 Oct 2026 Board exam · March 2026 hsc 12th Save WhatsApp Report

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Answer: C. positive

Answer: (c) positive

For a series LCR circuit \(\tan\phi = \dfrac{X_L - X_C}{R}\). When \(X_L > X_C\) the numerator is positive, so \(\tan\phi\) is positive: the voltage leads the current and the circuit is inductive.

Doubtly AI · 27 Oct 2026 AI-verified · Oct 2026 Report

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In series LCR circuit for \(X_L > X_C\), \(\tan\phi\) will be _____.

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